What do you think of this?

Stefan Härtel · October 26, 2003, 19:38

Here's the first couple of graphics from my coming scenario. No details are yet to be revealed, but guesses are premitted

Case · October 26, 2003, 19:45

That math stuff makes my head hurt

The graphics look great though

I'd guess that it's some kind of exploration scenario.

POTUS · October 26, 2003, 19:47

I don't do math.

Nice graphic.

Arthedain · October 26, 2003, 19:51

really nice waterfall!

Stefan Härtel · October 26, 2003, 19:55

That's supposed to be [i]easy](i] stuff I've got to know for my final exams in May (Meaning: I won't ever make it).

I just noticed you can't properly see the unit in the lower left corner after I've cut off the shield from the screenshot graphic.

The waterfall, BTW, will be only a small one of many elements in this scenario.

tanelorn · October 26, 2003, 20:47

Is he a stone-age hunter?
A Crusoe-type stranded on some island perhaps?

curtsibling · October 26, 2003, 20:57

Looks a bit Aztec!

Maths?

That's all Von Braun talk to me!

:) Smiley · October 26, 2003, 21:52

You forgot about the 3 * (-e^-x) terms in the binomial square

Harry Tuttle · October 26, 2003, 22:16

(3-(e^-x))(3-(e^-x))=9-3(e^-x)-3(e^-x)e^x Owwwww, a blood vessel just burst....

Stefan Härtel · October 27, 2003, 06:59

Well, the basic point is that the result must be:
f'(x)=(3-e^-x)² if f(x) is what would be F(x).
I personally think it must be F(x)=(x-e^-x)³; but I'd love to be proved otherwise

(basically this is just a maths problem that's been keeping me occupied the other night, and I wanted to hear a second opinion).

Quote:

Is he a stone-age hunter?
A Crusoe-type stranded on some island perhaps?

Nope. No island.

Quote:

Looks a bit Aztec!

Closer, but still far away.

Mercator · October 27, 2003, 13:36

The integral will be much more complicated than that... You also have the chain rule to worry about.

Try typing in the formula on this site:
http://integrals.wolfram.com/index.en.cgi

(Be sure to use uppercase E for e)

Stefan Härtel · October 27, 2003, 13:55

The result doesn't show

(it won't load the image)

If F(x) would be (x-e^-x)³, then f(x) would be, according to the chain rule: f(x)=(3-3^-x)²; or would it? According to
f'(x)=2*(3-e^-x)*e^-x if f(x)=(3-e-^x)²

In another calculation, however, f'(x) would be f'(x)=3*(x-e^-x)*(3-e^-x)

This is sick

curtsibling · October 27, 2003, 14:47

OK, Stefan!

Spill the beans!

What is the scenario about?
Not mathematics surely?

Mercator · October 27, 2003, 15:11

Quote:

Originally posted by Stefan Härtel
The result doesn't show

(it won't load the image)

I attached the image I got... It looks rather more complicated than the possible outcomes you gave. I'm not sure if that's because the program tries to write out everything in full... I.e. it would say x² - 2x + 1 rather than (x - 1)².

Quote:

If F(x) would be (x-e^-x)³, then f(x) would be, according to the chain rule: f(x)=(3-3^-x)²; or would it?

No, it would be:

3 * (x - e^-x)² * (1 + e^-x)

So you made two mistakes:
- The multiplier of 3 is outside the square. I.e. the derivative of x³ is 3(x²), not (3x)².
- You have to take the derivative of the part in parentheses as well, and use the chain rule... that's the (1 + e^-x) at the end.

Quote:

This is sick

I'll say... I'm glad I got that behind me. Not that the statistical maths I have to deal with is any easier, though.

EDIT: I forgot the minus in (1 + e^-x)

Stefan Härtel · October 27, 2003, 15:32

I have much to learn

(I've got one point out of 15 at best, that's a 5- mark, but it's enough since I'm good at English).

Quote:

OK, Stefan!

Spill the beans!

What is the scenario about?
Not mathematics surely?

No, I just posted the poll because I went nuts about the problem

I can't tell you exactly what the scenario will be about because that'd be telling too much. But I can tell you that it's an adventure scenario set in pre-Colombian Ecuador. I've got some very cool ideas so far, but I don't want to tell because that'd spoil too many surprises.

Mercator · October 27, 2003, 15:36

Yikes... You'd better ignore that attached image. The site doesn't seem to be too good at resolving those fractions (?).

If you try to get the integral of 3 * (x - e^-x)² * (1 + e^-x) the result looks really ugly...

Try this site, instead:
http://www.calc101.com/

You have to pay if you want a full step-by-step explanation for the integration. Without a password, it still shows the end result.

Mercator · October 27, 2003, 15:40

calc101.com makes the solution to your original question look a lot better (although still not quite as simple as you hoped):

Cyrion · November 3, 2003, 17:44

Quote:

Originally posted by Stefan Härtel I can't tell you exactly what the scenario will be about because that'd be telling too much. But I can tell you that it's an adventure scenario set in pre-Colombian Ecuador. I've got some very cool ideas so far, but I don't want to tell because that'd spoil too many surprises.

I'm unable to guess what your scen will be about, but what I can guess for sure is that I'll have MUCH pleausre playing it!

The graphical extract looks great, BTW!

Varwnos · November 4, 2003, 06:55

the pic looks wonderful Stefan! good work

Exile · November 4, 2003, 13:26

An official "no comment" on the mathematics from hell, Stefan.

Sounds like an exploration/conquest scenario about the rise of the Inca empire? The Chimu culture?

Alternatively, if it's about the European exploration, then it could be either Pizzarro's or Orelana's expeditions into the region. The term "pre-Columbian" seems to deny this last guess, however.

curtsibling · November 4, 2003, 13:44

I know!

The scen is about conquistadors using advanced mathematics to defeat the Incas!

Stefan Härtel · November 5, 2003, 11:58

Quote:

The scen is about conquistadors using advanced mathematics to defeat the Incas!

You'd play the Incas in that one, no doubt!

But... no. It's neither about the Incas or the Europeans (not even the Chimu).