April 14, 2003, 18:59
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#1
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Emperor
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This math question can't be very hard, right?
If we assume that we use 15% more money on something every year from 1978 to 1987, how do we figure out the total increase during the time span?
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April 14, 2003, 19:01
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#2
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President of the OT
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Very simple.
Money = (StartMoney X (1.15)# of years) - StartMoney
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"I'll never doubt you again when it comes to hockey, [Prince] Asher." - Guynemer
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April 14, 2003, 19:08
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#3
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Emperor
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Thank you sir, that was most welcome.
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April 14, 2003, 19:08
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#4
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Emperor
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You've had that "world leader" a bit long Monk dear boy...
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April 14, 2003, 19:12
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#5
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Emperor
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Hello there old chap! How are things? I figure no harm will be done threadjacking this one.
I am absolute incapable of finding or creating avatars, so I'm stuck with whatever I've got until Stefu's mercy provides another. You're absolutely right though, I have to find another trendy leader.
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April 14, 2003, 19:15
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#6
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Emperor
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Hmm... who's trendy enough to be in a Monk avatar?
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April 14, 2003, 19:19
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#7
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Deity
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I give you the President of Kazahkstan.
Find more leaders (as of 2000) here:
http://edition.cnn.com/2000/US/09/05...it.names.reut/
__________________
"Everybody knows you never go full retard. You went full retard man. Never go full retard"
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April 14, 2003, 19:20
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#8
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Emperor
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Erm... don't tell anybody, but I've always liked Joschka Fischer, I think he seems like a genuinely cool dude. Then again, my German friend (a CSU supporter) tells me I'd think differently if I had a clue. What led you to that avatar?
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April 14, 2003, 19:21
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#9
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Deity
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I like this one, the PM of Chad.
He has a mad stare there.
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"Everybody knows you never go full retard. You went full retard man. Never go full retard"
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April 14, 2003, 19:21
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#10
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Civ4: Colonization Content Editor
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Isn't the answer rather
StartMoney * (1 + 1.15 + 1.15² + 1.15³ + ... + 1.159 - 10) ?
This is not what Asher wrote, or did I understand the problem wrong. For example, you spend 1000 in 1978, 1150 in 1979, 1322.50 in 1980 etc. and you ask, how many more than 1000 per year you spent in the end? If so, Ashers solution sounds wrong.
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April 14, 2003, 19:22
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#11
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Emperor
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Wow, the Kazahk Prez. You know what, that could work. I'm checking out a couple others right now, thanks a lot for the link.
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April 14, 2003, 19:25
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#12
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Emperor
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Aaaah, no, Sir Ralph!
Why'd you have to go and make things so complicated?
Your interpretation is, I think, correct, though I can't say if your answer is. But now I'm confusing myself and probably the rest of you too.
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April 14, 2003, 19:29
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#13
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Deity
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Quote:
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Originally posted by Sir Ralph
Isn't the answer rather
StartMoney * (1 + 1.15 + 1.15² + 1.15³ + ... + 1.159 - 10) ?
This is not what Asher wrote, or did I understand the problem wrong. For example, you spend 1000 in 1978, 1150 in 1979, 1322.50 in 1980 etc. and you ask, how many more than 1000 per year you spent in the end? If so, Ashers solution sounds wrong.
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The increase is what Asher wrote. The cumulative increase is what you have written. Not sure which Monk was after though.
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"Everybody knows you never go full retard. You went full retard man. Never go full retard"
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April 14, 2003, 19:29
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#14
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Civ4: Colonization Content Editor
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If my interpretation is correct, the my solution should be correct too. In this case, the solution is
SUM(n from 0 to 9)(1.15n) - SUM(n from 0 to 9)(1)
The former term is 1 + 1.15 + 1.15² ..., the latter term is 10.
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April 14, 2003, 19:30
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#15
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Monk :
Who's on your avatar ?
Others :
Can you continue the following pattern ?
1
11
21
1211
111221
312211
13112221
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April 14, 2003, 19:32
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#16
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Civ4: Colonization Content Editor
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Quote:
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Originally posted by Big Crunch
The increase is what Asher wrote. The cumulative increase is what you have written. Not sure which Monk was after though.
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Well, he wrote total increase...
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April 14, 2003, 19:35
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#17
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Deity
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Edit:
Actually that was wrong and forever immortalised in the following post.
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"Everybody knows you never go full retard. You went full retard man. Never go full retard"
Last edited by Dauphin; April 14, 2003 at 19:46.
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April 14, 2003, 19:37
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#18
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Civ4: Colonization Content Editor
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Quote:
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Originally posted by Big Crunch
Quote:
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SUM(n from 0 to 9)(1.15n) - SUM(n from 0 to 9)(1)
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or
1/r[1 + 1/(1-r)n]
Where r is the % increase each year and n is the number of years.
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 Please be merciful with me, it's 1:45am, and I have digged my formula books very deep under.
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April 14, 2003, 19:41
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#19
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Emperor
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Okay, I'm sorry if I've been unclear on some points. The task was to compare the 1978 and 1987 numbers - that is, to find out how many percent constituted the total increase from 1978 to 1987 assuming a 15% increase every year. I think the answer would have to be 22.5%.
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April 14, 2003, 20:39
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#20
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President of the OT
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I assumed what he was looking for was equivalent to compound interest...
I don't know if that's what he's looking for, but that's how I interpreted it.
__________________
"I'll never doubt you again when it comes to hockey, [Prince] Asher." - Guynemer
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April 14, 2003, 23:17
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#21
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Guest
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1
11
21
1211
111221
312211
13112221
1113213211
31131211131221
way too classic by now
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